Proof by Tautology 1
1.) A ∧ B Assume
2.) ¬[¬(A ∧ B)] t8
3.) ¬[(¬A ∨ ¬B)] De Morgan's First Law
∴ (A ∧ B) ⇔ ¬[(¬A ∨ ¬B)] Conclusion
Each line in this proof is equivalent to the next. The transitive property allows for the "detachment" and/or "addition" of propositions. Since each line from the first is a tautology built from line one, each proposition must therefore be equivalent to the first.
Proof by Tautology 2
1.) ¬A ∧ ¬B Assume
2.) ¬{[¬(¬A)] ∨ ¬(¬B)]} Proof by Tautology 1
3.) ¬{A ∨ B} Complete Law of Double Negation
∴ ¬A ∧ ¬B ⇔ ¬{A ∨ B} Conclusion
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