Thursday, June 30, 2016

The Product Rule (Calculus)

Assume u = f(x) and v = g(x) are both positive differentiable functions.  Then the product uv can be interpreted as the area of a rectangle. If x changes by an amount △x, then the corresponding changes in u and v are 

△u = f(x + △x) - f(x) and △v = g(x + △x) - g(x)

And the value of the product (u + △u)(v + △v) can be interpreted as the area of the largest rectangle above. The change in the rectangle then is 

△(uv) = (u + △u)(v + △v) - uv = u△v + v△u + △u△v

Or in other words the sum of the three shaded regions above. Now dividing by △x, yields

△(uv)/△x = u(△v/△x) + v(△u/△x) + △u(△v/△x)

Now take the limit of △(uv)/△x as △x ⟶ 0 and you get the derivative of uv:

d(uv)/dx = u lim△x⟶0(△v/△x) + v lim△x⟶0(△u/△x) +  lim△x⟶0(△u) lim△x⟶0(△v/△x)

d(uv)/dx = u(dv/dx) + v (du/dx) +  0 (dv/dx)

d(uv)/dx = u(dv/dx) + v (du/dx)

Thursday, June 2, 2016

Calculus

A function is a rule that assigns each element in a set D to exactly one element in a set R.

If f is an even function, then f(-x) = f(x) for all x. If f is an odd function, then f(-x) = -f(x) for all x. f(x) = x^2 is an even function because f(-x) = (-x)^2 = (-x)(-x) = x^2 = f(x). f(x) = x^3 is an odd function because f(-x) = (-x)^3 = (-x)(-x)(-x) = (-x)x^2 = -(x^3) = -f(x). Odd functions are symmetric with respect to the origin. Even functions are symmetric with respect to the y-axis.

A function is called increasing on an interval I if for all x1 < x2 in I, f(x1) < f(x2). And a function is called decreasing on an interval I if for all x1 < x2 in I, f(x1) > f(x2).